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Monty Hall, we have a PROBLEM

Re: Monty Hall, we have a PROBLEM

FreshFish said:
This is a pretty old one and was a lot more challenging before internet search engines became so robust.

Name the colleges/universities that can count among their graduates both a President of the United States, and a Super Bowl winning quarterback.

Bonus: name the Presidents and quarterbacks.


PS if anyone wants a hint or two, LMK and I can post it in white text.
Click to expand...

Miami: Benjamin Harrison, Ben R-something I can't spell
Michigan: Gerald Ford, Tom Brady
Navy: Jimmy Carter?
Stanford: John Elway?

Navy's QB and Stanford's president in white text, of course.
 
Re: Monty Hall, we have a PROBLEM

Critical Thinker said:
Miami: Benjamin Harrison, Ben R-something I can't spell
Michigan: Gerald Ford, Tom Brady
Navy: Jimmy Carter?
Stanford: John Elway?

Navy's QB and Stanford's president in white text, of course.
Click to expand...

Sorry it took me so long to respond. answers as requested below in white:

Navy QB was Roger Staubach. For Stanford, Jim Plunkett was a 2nd QB and the President was Herbert Hoover.
 
Re: Monty Hall, we have a PROBLEM

Three people are traveling through the desert and stop at an oasis for the evening. One has three loaves of bread, the other has five loaves of bread, the third has eight coins to offer. They decide to share the bread equally, and the third will compensate the other two in proportion to their contribution to his meal.

How many coins does each of the first two people get?
 
Re: Monty Hall, we have a PROBLEM

FreshFish said:
Three people are traveling through the desert and stop at an oasis for the evening. One has three loaves of bread, the other has five loaves of bread, the third has eight coins to offer. They decide to share the bread equally, and the third will compensate the other two in proportion to their contribution to his meal.

How many coins does each of the first two people get?
Click to expand...

I am bored today. Each gets 2 2/3 (one third of 3 plus 5) loaves of bread. So the first person needs to be compensated by the third for 1/3 loaf and the second needs to be compensated by the third for 2 1/3 loaves, a ratio of 1 to 7. Thus the third gives one coin to the first and 7 to the second. Actually the statement doesn't say that the third should spend all of his coins, so it could be 1/2 coin to the first and 3 1/2 to the second or something else requiring breaking coins.
 
Re: Monty Hall, we have a PROBLEM

FreshFish said:
Three people are traveling through the desert and stop at an oasis for the evening. One has three loaves of bread, the other has five loaves of bread, the third has eight coins to offer. They decide to share the bread equally, and the third will compensate the other two in proportion to their contribution to his meal.

How many coins does each of the first two people get?
Click to expand...
4 each. They shot the 3rd guy for not bringing food.

Now if it was 3 loaves and 5 fishes, I'd look awfully close at the 3rd guy!!
 
Re: Monty Hall, we have a PROBLEM

FreshFish said:
Three people are traveling through the desert and stop at an oasis for the evening. One has three loaves of bread, the other has five loaves of bread, the third has eight coins to offer. They decide to share the bread equally, and the third will compensate the other two in proportion to their contribution to his meal.

How many coins does each of the first two people get?
Click to expand...

Pretty sure this is just a fractions problem.

Man 1 gives a 1/3 of a loaf and gets one coin. Man 2 gives 2 1/3 loafs and gets 7 coins.
 
Re: Monty Hall, we have a PROBLEM

You are making a decoration for the holidays. You want to make a simple sign that counts down the days until Christmas that won't be used at the earliest until the Saturday after Thanksgiving.

You will use two cubes, that will fit side-by-side into a slot on the sign, so that a person can adjust them every day to read the correct number of days left.

How do you number each side of the two cubes so that you can represent every day that is needed?


Hint in white:

There is a "trick" involved.



PS kudos to Ralph, our reigning breadcoins champion.
 
FreshFish said:
You are making a decoration for the holidays. You want to make a simple sign that counts down the days until Christmas that won't be used at the earliest until the Saturday after Thanksgiving.

You will use two cubes, that will fit side-by-side into a slot on the sign, so that a person can adjust them every day to read the correct number of days left.

How do you number each side of the two cubes so that you can represent every day that is needed?


Hint in white:

There is a "trick" involved.



PS kudos to Ralph, our reigning breadcoins champion.
Click to expand...

if you can't leave the first one blank for single digits:
One cube has: 1,2,4,5,6,0
The other cube has: 1,2,3,7,8,0.

6 becomes 9 when flipped upside down.

If you can leave the first one empty, no trick needed. One has 1-6, the other has 0-2 & 7-9.
 
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Re: Monty Hall, we have a PROBLEM

“Nothing happens. Nobody comes, nobody goes. It's awful.”

You guys do realize that you're not disagreeing with each other, right?
 
Re: Monty Hall, we have a PROBLEM

LynahFan said:
You guys do realize that you're not disagreeing with each other, right?
Click to expand...


Hmm....that actually is a very thorny problem in logic: is "not disagreeing" the same thing as "agreeing"?



Some would say yes: everything can be boiled down to an either / or choice: P + ~P = A




There is another logical system that allows for three equally valied choices:

P = True AND ~ P = False
or
Both P = True AND ~ P = True
or
Both P = False AND ~ P = False.


There is a physics experiment that indicates that the world operates by the latter logical system, not the former (or maybe neither of these?).

Take two polarizing filters (polarizing in the sense of aligning the vibration pattern of light waves, not in the sense of driving people to further extremes in an argument. ;) )

Align one vertically and one horizontally then shine light through both of them. No light gets through.

Now add a third polarizing filter, aligned at 45[SUP]o[/SUP]. If you place it in front of the vertical one, or behind the horizontal one, no light gets through.

However, if you place it in between the other two, light gets through! (I've done this in a lab, it's awesomely amazing).

This outcome is "impossible" by classical logic, yet it happens.
 
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LynahFan said:
“Nothing happens. Nobody comes, nobody goes. It's awful.”

You guys do realize that you're not disagreeing with each other, right?
Click to expand...

You took the LSAT, word order matters for logic problems. Joe's last statement is not correct. "Not all rectangles are squares" is true. "All rectangles are not squares" is false.
 
Re: Monty Hall, we have a PROBLEM

In the past few months, I came across a number puzzle called KenKen. Far more interesting than Sudoku.
 
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