Originally posted by

**LynahFan**View PostI'm actually curious now how fast a "normal" train would have to go.

Ok, super quick math:

V = (220k tons / 5k tons * (13.5 knots)^2) ^ 0.5 = 103 mph

Initially I forgot to include the 13.5^2 inside the square root and laughed very hard at the answer until I realized where I went wrong.

Anyways, imagine a fully loaded train at 103 mph running into the side of a mountain. That's the energy here.

## Comment